Last updated at Feb. 1, 2020 by Teachoo

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Ex 11.2, 7 The Cartesian equation of a line is (๐ฅ โ 5)/3 = (๐ฆ + 4)/7 = (๐ง โ 6)/2. Write its vector form.Cartesian equation : (๐ฅ โ 5)/3 = (๐ฆ + 4)/7 = (๐ง โ 6)/2 (๐ฅ โ 5)/3 = (๐ฆ โ (โ4))/7 = (๐ง โ 6)/2 Equation of a line in Cartesian form is given by (๐ฅ โ ๐ฅ1)/๐ = (๐ฆ โ ๐ฆ1)/๐ = (๐ง โ ๐ง1)/๐ Comparing (1) and (2), ๐ฅ1 = 5, ๐ฆ1 = โ4, ๐ง1 = 6 ๐ = 3, b = 7, c = 2 Cartesian equation : (๐ฅ โ 5)/3 = (๐ฆ + 4)/7 = (๐ง โ 6)/2 (๐ฅ โ 5)/3 = (๐ฆ โ (โ4))/7 = (๐ง โ 6)/2 Equation of a line in Cartesian form is given by (๐ฅ โ ๐ฅ1)/๐ = (๐ฆ โ ๐ฆ1)/๐ = (๐ง โ ๐ง1)/๐ Comparing (1) and (2), ๐ฅ1 = 5, ๐ฆ1 = โ4, ๐ง1 = 6 ๐ = 3, b = 7, c = 2 Equation of line in vector form is ๐ โ = ๐ โ + ๐๐ โ Where ๐ โ = ๐ฅ1๐ ฬ + y1๐ ฬ + z1๐ ฬ = 5๐ ฬ โ 4๐ ฬ + 6๐ ฬ & ๐ โ = ๐๐ ฬ + b๐ ฬ + c๐ ฬ = 3๐ ฬ + 7๐ ฬ + 2๐ ฬ Now, ๐ โ = (5๐ ฬ โ 4๐ ฬ + 6๐ ฬ) + ๐ (3๐ ฬ + 7๐ ฬ + 2๐ ฬ)

Ex 11.2

Ex 11.2, 1

Ex 11.2, 2

Ex 11.2, 3 Important

Ex 11.2, 4

Ex 11.2, 5 Important

Ex 11.2, 6

Ex 11.2, 7 Important You are here

Ex 11.2, 8

Ex 11.2, 9 Important

Ex 11.2, 10 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 10 (ii)

Ex 11.2, 11 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 11 (ii)

Ex 11.2, 12 Important

Ex 11.2, 13

Ex 11.2, 14 Important

Ex 11.2, 15 Important

Ex 11.2, 16

Ex 11.2, 17 Important

Chapter 11 Class 12 Three Dimensional Geometry (Term 2)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.